What is the maximum flow rate for a 1 1/2 inch pipe to stay below 5 feet per second?

Prepare for the Texas Irrigation Technician Test with flashcards and multiple choice questions. Each question has detailed hints and explanations. Get ready to pass your exam with confidence!

To determine the maximum flow rate for a 1 1/2 inch pipe while keeping the flow velocity below 5 feet per second, you need to consider the cross-sectional area of the pipe and the relationship between flow rate and velocity.

The diameter of a 1 1/2 inch pipe is approximately 1.5 inches, which can be converted to feet as 1.5/12 = 0.125 feet. The cross-sectional area of the pipe can be found using the formula for the area of a circle (A = πr²). The radius in feet is 0.125/2 = 0.0625 feet. Therefore, the cross-sectional area is calculated as:

A = π * (0.0625)² ≈ 0.01227 square feet.

Flow rate (Q) can be calculated using the formula Q = A * v, where "Q" is the flow rate in cubic feet per second, "A" is the area in square feet, and "v" is the velocity in feet per second. Plugging the maximum velocity of 5 ft/s into this formula gives us:

Q = 0.01227 square feet * 5 feet/second ≈

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